I have a sample question whose answer seems just wrong:
Since the radius of the disk is:
. . . . .\(\displaystyle R(x)\, =\, 4\sqrt{3\,}\, -\, 4\sqrt{x\,},\,\)
then the volume is:
. . . . .\(\displaystyle \displaystyle V\, =\, \int_0^3\, \pi\, \left(\, 4\sqrt{3\,}\, -\, 4\sqrt{x\,}\,\right)^2\, dx\, =\, 24\pi \mbox{ cubit units}\)
But this answer seems wrong
Since the radius of the disk is:
. . . . .\(\displaystyle R(x)\, =\, 4\sqrt{3\,}\, -\, 4\sqrt{x\,},\,\)
then the volume is:
. . . . .\(\displaystyle \displaystyle V\, =\, \int_0^3\, \pi\, \left(\, 4\sqrt{3\,}\, -\, 4\sqrt{x\,}\,\right)^2\, dx\, =\, 24\pi \mbox{ cubit units}\)
But this answer seems wrong
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