chromechris
New member
- Joined
- Jan 21, 2018
- Messages
- 24
[MATH]\frac{y-6}{4}-\frac{2y+5}{2}=-7[/MATH]
[MATH](4)\frac{y-6}{4}-(4)\frac{2y+5}{2}=(4)-7[/MATH]
Where I have an issue: ()I don't know whether to distribute [MATH(2)][/MATH] or [MATH](-2)[/MATH] to the [MATH](2y+5)[/MATH] (How do I decide what to distribute?)
[MATH]y-6-(2)2y+5=-28[/MATH]
What I want to do it, but I get a wrong answer:
[MATH]y-6-4y+10=-28[/MATH][MATH]y=\frac{32}{3}[/MATH]
A different way I tried it and got the correct answer:
[MATH]y-6-4y-10=-28[/MATH][MATH]y=4[/MATH]
[MATH](4)\frac{y-6}{4}-(4)\frac{2y+5}{2}=(4)-7[/MATH]
Where I have an issue: ()I don't know whether to distribute [MATH(2)][/MATH] or [MATH](-2)[/MATH] to the [MATH](2y+5)[/MATH] (How do I decide what to distribute?)
[MATH]y-6-(2)2y+5=-28[/MATH]
What I want to do it, but I get a wrong answer:
[MATH]y-6-4y+10=-28[/MATH][MATH]y=\frac{32}{3}[/MATH]
A different way I tried it and got the correct answer:
[MATH]y-6-4y-10=-28[/MATH][MATH]y=4[/MATH]