distributive property

raywil4

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Apr 22, 2013
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How do i solve 8 and 5/12ths + 8 and 7/12ths using the distributive property?
 
Hello, raywil4!

Where did this problem come from?
It doesn't make sense!


How do i solve 8 and 5/12ths + 8 and 7/12ths using the distributive property?

The distributive property says: .\(\displaystyle a(b+c)\:=\:ab+ac\)
. . It involves both addition and multiplication.

This problem has only addition: .\(\displaystyle 8 + \frac{5}{12} + 8 + \frac{7}{12}\)
 
Hello, raywil4!

Where did this problem come from?
It doesn't make sense!


The distributive property says: .\(\displaystyle a(b+c)\:=\:ab+ac\)
. . It involves both addition and multiplication.

This problem has only addition: .\(\displaystyle 8 + \frac{5}{12} + 8 + \frac{7}{12}\)

Perhaps reversed distributive property,
101*(1/12) + 103*(1/12) = 204*(1/12)
 
How do i solve 8 and 5/12ths + 8 and 7/12ths using the distributive property?

I believe this was meant to be solved as such:

\(\displaystyle 8\frac{5}{12}+8\frac{7}{12}\ can \ be \ rewritten \ as:\)

\(\displaystyle 8(\frac{5}{12}+\frac{7}{12})=\)

Now distribute:

\(\displaystyle 8*\frac{5}{12}+8*\frac{7}{12}=\)


\(\displaystyle \frac{40}{12}+\frac{56}{12}=\)

\(\displaystyle \frac{96}{12}=8\)
 
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