Dividing measurements by cube root of corresponding volume produces higher Coefficients of Variation how can this be?

Soleil14

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Aug 12, 2020
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(CV - coefficient of variation)
Please please help me understand my data. Explain to me why the 'CV corrected' mean is higher than the regular CV mean.
This table shows measurements for 8 variables for 6 specimens. It also includes the volume. In the 'corrected' columns, I have divided each value by the cube root of the corresponding volume. I have then calculated the CV for the 'corrected values'. I really would have expected the average of these CV's to be lower.
Why is it higher?

What does it mean about my data?

Does it mean that once you remove size variation from the measurements there is more variation? That makes no sense! Please help
 

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