A number starts with the digit 4. if the 4 is removed and placed @ the end of the number , it is the smallest number divisible by 4 that this operation works on. What is the number ? I don't know how many digits are in the number, is it a case of trial & error ? Thank you.
Divisible number.
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A number starts with the digit 4. if the 4 is removed and placed @ the end of the number , it is the smallest number divisible by 4 that this operation works on. What is the number ? I don't know how many digits are in the number, is it a case of trial & error ? Thank you.
As I understand the instructions, the number would be 44
If you remove the 4 from the leading position and put it at the end - it will be still divisible by four and you can repeat the operation (the operation works on the resulting number).
Very poorly worded problem!!!
I agree with Subhotosh Khan that the problem is horribly worded, but as it is stated, the smallest POSITIVE number is not 44; it is either 4 or 40, unclear because "it" has an unclear antecedent.A number starts with the digit 4. if the 4 is removed and placed @ the end of the number , it is the smallest number divisible by 4 that this operation works on. What is the number ? I don't know how many digits are in the number, is it a case of trial & error ? Thank you.
f(40)=04=4=smallest positive number divisible by 4.
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A number starts with the digit 4. if the 4 is removed and placed @ the end of the number , it is the smallest number divisible by 4 that this operation works on. What is the number ? I don't know how many digits are in the number, is it a case of trial & error ? Thank you.
Is it the number that you got after moving 4 to end?
If it is then 40 becomes 04 - now you cannot have the operation repeated (because it does not start with 4)! However, 44 stays 44 - then you have the number on which the operation can work (again! - forever!!)
If I take 4 from the beginning of the number 4 and then put it at the end of what is left, the result is divisible by 4.Is it the number that you got after moving 4 to end?
If it is then 40 becomes 04 - now you cannot have the operation repeated (because it does not start with 4)! However, 44 stays 44 - then you have the number on which the operation can work (again! - forever!!)
A number starts with the digit 4. if the 4 is removed and placed @ the end of the number,
it is the smallest number divisible by 4 that this operation works on. What is the number ? I don't know how many
digits are in the number, is it a case of trial & error ? Thank you.
bigbill,
was there any different wording to this problem that you can type here?
If all of the following were to be in place, then I would go with the original number being 42:
a) The original number may or may not be divisible by 4.
b) When the digit 4 is placed as the last digit to form the resulting number (different or the same as the original number),
the first digit of the resulting number is not allowed to be a zero.
c) The original and new numbers are both positive integers.