Domain of Square Root Function

[harpazo]

Find domain of h(x) = sqrt{5 + 4x}.

Solution:

I know the radicand cannot be negative. I must equate 5 + 4x to be greater than or equal to 0.

5 + 4x ≥ 0

4x ≥ -5

x ≥ -5/4

Let d = domain

d = {x | x ≥ -5/4}

This tells me that x can safely be equal to -5/4 or greater than -5/4 for h(x). Correct?

 

[Harry_the_cat]

correct

 

[HallsofIvy]

Yes, that is correct.

 

[harpazo]

Wonderful. It feels good to get the right answer.