dy/dx=sqrt(x-y) Initial value: y(2)=2

spacejunkie

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Sep 1, 2006
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dy/dx=sqrt(x-y) Initial value: y(2)=2

I say solutions exist because

lim (x,y) approach (2,2) sqrt(x-y)=0 thus existence

My book says, "Neither existence nor uniqueness is guaranteed in any neighborhood of x=2."

I think I understand why uniqueness is not guaranteed but why not existence? Thank you for your help.
 
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