E and Var of two variables

Romi123

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Jan 9, 2021
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From deck of 52 cards numbered by 1-13, (each number has 4 cards) we choose two cards without replacement, the sum of the cards is X.
Then, we toss a coin X times, Y is the number of times 'Heads' shown.
what is the expected value and variance of Y?
 
Well you're going to have to come up with the probability distribution of Y. Can you do that?
 
X=26, X=25,...X=3, X=2
Y=26, Y=25, ..., Y=2, Y=1, Y=0.
p(Y=26)=?, p(Y=25)=?, ... p(Y=0)=?
 
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