Since \(\displaystyle 78 \:=\:52 + 26\), I assume that half the cards are duplicated.
For example: all the red cards \(\displaystyle (\heartsuit,\:\diamondsuit)\) have duplicates; . . . . . . . . . .the black cards \(\displaystyle (\spadesuit,\:\clubsuit)\) are normal.
The first person must draw a red card: .\(\displaystyle \dfrac{52}{78}\,=\,\dfrac{2}{3}\)
The second must draw its duplicate: .\(\displaystyle \dfrac{1}{77}\)
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.