Equation re-arrangement query

DJW

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May 24, 2021
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Hi,

I'm having trouble understanding the below re-arrangement.

Please note: B = 4 and Y1 = 2.25

I'm rusty on general rules. Can any help?

Thanks!


1621897855831.png
 
Hi,

I'm having trouble understanding the below re-arrangement.

Please note: B = 4 and Y1 = 2.25

I'm rusty on general rules. Can any help?

Thanks!


View attachment 27453
Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:


Please share your work/thoughts about this problem
 
Thank you, but sorry I forgot to mention V1 = 2
1621902469812.png

To start simplify:

\(\displaystyle \frac{10}{4*y_2} \ = \ \frac{V_1 * b * y_1}{b * y_2} \ + \ \frac{V_w * b * y_1}{b * y_2} - V_w \)

\(\displaystyle \frac{2.5}{y_2} \ = \ \frac{V_1 * y_1}{ y_2} \ + \ \frac{V_w * y_1}{ y_2} - V_w \).......,........,...................edited

move "terms" and isolate Vw and continue....
 
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So the question is [MATH]\; \dfrac{10}{4 \; y_2}=\dfrac{9(v_w+2)}{4 \; y_2}-v_w \hspace3ex [/MATH] (the b cancels top and bottom and [MATH]y_1 = 2.25= \tfrac{9}{4}[/MATH])

Multiply the 3 terms by [MATH] 4\;y_2[/MATH]so
[MATH]9(v_w+2)-4y_2v_w=10[/MATH]
Hopefully you can multiply that out, 'gather up' the [MATH]v_w[/MATH] terms and solve for [MATH]v_w[/MATH]
 
View attachment 27454

To start simplify:

\(\displaystyle \frac{10}{4*y_2} \ = \ \frac{V_1 * b * y_1}{b * y_2} \ + \ \frac{V_w * b * y_1}{b * y_2} - V_w \)

\(\displaystyle \frac{2.25}{y_2} \ = \ \frac{V_1 * y_1}{ y_2} \ + \ \frac{V_w * y_1}{ y_2} - V_w \)

move "terms" and isolate Vw and continue....


Thank you Subhotosh!

I understand the right hand side (expanding out), but how did the 2.25 on the left come about? sorry if this is simple, just been a long time for me. Really appreciate your help
 
Thank you Subhotosh!

I understand the right hand side (expanding out), but how did the 2.25 on the left come about? sorry if this is simple, just been a long time for me. Really appreciate your help
Good catch ...... That should have been 2.5 as in:

\(\displaystyle \frac{10}{4} \ = 2.5 \)

I have edited my previous response.
 
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