T tiigrike New member Joined Oct 30, 2011 Messages 12 Mar 20, 2012 #1 I have equation like this: Q=((a-2b)±√(a^2+4ab+4b^2-8bc))/4b How i get the solution? And what conditions i get , like b is not 0, but a and c?
I have equation like this: Q=((a-2b)±√(a^2+4ab+4b^2-8bc))/4b How i get the solution? And what conditions i get , like b is not 0, but a and c?
D Deleted member 4993 Guest Mar 20, 2012 #2 tiigrike said: I have equation like this: Q=((a-2b)±√(a^2+4ab+4b^2-8bc))/4b How i get the solution? And what conditions i get , like b is not 0, but a and c? Click to expand... As posted, you can have b = 0 [ you posted Q=((a-2*b)±√(a^2+4*a*b+4*b^2-8*b*c))/4 * b] you probably should have posted: Q=((a-2*b)±√(a^2+4*a*b+4*b^2-8*b*c))/[4 * b] Anyway, I am not sure what you do mean by "solution". Please expound. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
tiigrike said: I have equation like this: Q=((a-2b)±√(a^2+4ab+4b^2-8bc))/4b How i get the solution? And what conditions i get , like b is not 0, but a and c? Click to expand... As posted, you can have b = 0 [ you posted Q=((a-2*b)±√(a^2+4*a*b+4*b^2-8*b*c))/4 * b] you probably should have posted: Q=((a-2*b)±√(a^2+4*a*b+4*b^2-8*b*c))/[4 * b] Anyway, I am not sure what you do mean by "solution". Please expound. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
H HallsofIvy Elite Member Joined Jan 27, 2012 Messages 7,760 Mar 21, 2012 #3 Solve for which "unknown"?
