If you are trying to prove the given identity, "cross multiplying" won't cut it. (In my opinion you should eliminate "cross multiply" from your vocabulary.) However, if you do some grouping you can multiply both numerator and denominator by ((1+sin(x)) + cos(x)). This will result in... (1+sinx)2−cos2x(1+sinx)2+2(1+sinx)cosx+cos2x
Then plenty of simplification results in the desired outcome.
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