establish the identity

justseel

New member
Joined
Apr 8, 2014
Messages
2
My math teacher ask me to establish the identity in two ways
from right side to the left side
and from left ti right
sec=sin/cos + cos/1+sin
 
My math teacher ask me to establish the identity in two ways
from right side to the left side
and from left ti right
sec=sin/cos + cos/1+sin

What have you tried?

What are your thoughts?

Please share your work with us ...

If you are stuck at the beginning tell us and we'll start with the definitions.

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yes I,m stuck at the beginning
i tired to do this but i didnt know how e
nd it
1/cosx = sinx+1/cosxsinxcosx
:confused:
 
Greetings:

A hint: Try multiplying numerator and denominator of cosx/(1+sinx) by the conjugate of 1 + sinx.

Rich
 
Last edited:
Enough time has gone by: Right to left

sin(θ)cos(θ)+cos(θ)1+sin(θ)\displaystyle \dfrac{sin(\theta)}{cos(\theta)} + \dfrac{cos(\theta)}{1+sin(\theta)}

= sin(θ)[1+sin(θ)]+cos2(θ)cos(θ)[1+sin(θ)]\displaystyle = \ \dfrac{sin(\theta)*[1+sin(\theta)] + cos^2(\theta)}{cos(\theta)*[1+sin(\theta)]}

= 1+sin(θ)cos(θ)[1+sin(θ)]\displaystyle = \ \dfrac{1+sin(\theta)}{cos(\theta)*[1+sin(\theta)]}

= 1cos(θ)\displaystyle = \ \dfrac{1}{cos(\theta)}

= sec(θ)\displaystyle = \ sec(\theta)

Now just go back-wards.... for left-to-right
 
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