Evaluate Lt x -> 0 (3/2 + x - 3x2 + 5x3)

Sarguru

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Please help me to solve this question from calculus,

Evaluate Lt x -> 0 (3/2 + x - 3x2 + 5x3)

Thanks in advance. Your support is very much appreciated ☺
 
Is it limit x->0 of \(\displaystyle \frac{3}{2} + x -3x^2 + 5x^3\) or \(\displaystyle \frac{3}{2+x} - 3x^2 + 5x^3\) or something else?
 
Evaluate Lt x -> 0 (3/2 + x - 3x2 + 5x3)
Hi Sarguru. We type the caret symbol ^ to show exponents:

lim x->0 [5x^3 - 3x^2 + x + 3/2]

y = 5x^3 - 3x^2 + x + 3/2 is a polynomial equation.

All polynomial graphs are smooth, continuous curves. There are no gaps or sharp turns. If we trace along such a curve, as x approaches zero, then we are approaching the y-intercept.

The limit asks: What number is y approaching, as x gets closer and closer to zero?

?
 
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