Evaluate the value for the expression (sqrt(x))^(4*log_x(a))

suhasbadiger

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Please help me in finding the value of given question:

The value of (x)4logx(a)\left( \sqrt{x} \right)^{4\, \log_x(a)} is:

(i) aa
(ii) axax
(iii) 12ax\frac{1}{2}\,ax
(iv) a2a^2
 

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Please help me in finding the value of given question in attachment

The value of (x)4logx(a)\left( \sqrt{x} \right)^{4\, \log_x(a)} is:

(i) aa
(ii) axax
(iii) 12ax\frac{1}{2}\,ax
(iv) a2a^2

We're eager to help, but we need to see where you need help; our help doesn't consist of just giving you the answer.

Please show what you have tried, and where you are stuck. I might start, if I were you, by writing the radical as a fractional power, using exponent properties to simplify the expression, then use the inverse property of the log to finish up.
 
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Hint:
1) write x as x1/2\displaystyle \sqrt x\ as\ x^{1/2}
2) note that xlogx(anything) = anything and rlogxa = logxar
 
You are studying algebra. Use it.

y=(x)4logx(a)=(x1/2)4logx(a)=x2logx(a)    logx(y)=logx(x2logx(a))=2logx(a)logx(x)=2logx(a)1=2logx(a).Now continue and solve for y. y = ( \sqrt{x} )^{4 \log_x (a)} = (x^{1/2})^{4 \log_x(a)} = x^{2 \log_x(a)} \implies \\ \log_x (y) = \log_x(x^{2\log_x(a)})= 2\log_x(a) * \log_x(x) = 2 \log_x(a) * 1 = 2 \log_x(a).\\ \text {Now continue and solve for y.}
This is effectively the same as the hint that Stephen G gave you. The difference is that mine relies on memorizing fewer log rules and instead applying more algebra.
 
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