K K_Swiss New member Joined Feb 8, 2008 Messages 28 Jan 16, 2009 #1 Evaluate \(\displaystyle e^{2ln4}\) using properties of the logarithm. I used a calculator to solve this question and I got 16, but I don't know how to solve this without a calculator... Please help?
Evaluate \(\displaystyle e^{2ln4}\) using properties of the logarithm. I used a calculator to solve this question and I got 16, but I don't know how to solve this without a calculator... Please help?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Jan 16, 2009 #2 It's easy using the properties of logs. Remember that e 'cancels out' ln because e is the base of ln. \(\displaystyle e^{2ln(4)}=e^{ln(4^{2})}=4^{2}=16\) See?.
It's easy using the properties of logs. Remember that e 'cancels out' ln because e is the base of ln. \(\displaystyle e^{2ln(4)}=e^{ln(4^{2})}=4^{2}=16\) See?.
K K_Swiss New member Joined Feb 8, 2008 Messages 28 Jan 16, 2009 #3 yes I see it. thank you for your help!
