I'm studying part b). When the manual says:
\(\displaystyle \frac{1}{\sqrt{2\pi}}\int^N_{-N}e^{-u^2/2}\;du=\frac{2}{\sqrt{2\pi}}\int^{N}_{0}e^{-u^2/2}\;du\)
I am a little curious about how exactly \(\displaystyle \frac{1}{\sqrt{2\pi}}\) becomes \(\displaystyle \frac{2}{\sqrt{2\pi}}\).
The only logic I can really apply would be that since the interval was halved that the constant on the outside of the integral sign was also divided by two however I'm not really sure if that is the case or if that is really even possible to do with definite integrals.
Thanks in advance for any responses...
Last edited: