Hey guys. I was pretty sure I had this down but clearly I messed something up. Here's what I have:
3^(n+4)=27^(2n)
Solving for n:
3^(n+4)=(3^3)^(2n)
3^(n+4)=3^6n
n+4=6n
4=5n
4/5=n
I was so sure this was right but my calculator says it's false. Please tell me where I went wrong!
Thanks guys.
3^(n+4)=27^(2n)
Solving for n:
3^(n+4)=(3^3)^(2n)
3^(n+4)=3^6n
n+4=6n
4=5n
4/5=n
I was so sure this was right but my calculator says it's false. Please tell me where I went wrong!
Thanks guys.