N NadroJV13 New member Joined Feb 3, 2009 Messages 7 Apr 30, 2009 #1 Could someone help me expand this logarithm using the laws of lagarithms... log ( 10x/x(x^4+5)(x^6+4) ) My best guess was... x-logx-log(x^4+5)-log(x^6+4) thanks
Could someone help me expand this logarithm using the laws of lagarithms... log ( 10x/x(x^4+5)(x^6+4) ) My best guess was... x-logx-log(x^4+5)-log(x^6+4) thanks
D Denis Senior Member Joined Feb 17, 2004 Messages 1,700 Apr 30, 2009 #2 NadroJV13 said: My best guess was... Click to expand... "guess" ?
D Deleted member 4993 Guest May 1, 2009 #3 NadroJV13 said: Could someone help me expand this logarithm using the laws of lagarithms... log ( 10x/x(x^4+5)(x^6+4) ) My best guess was... x-logx-log(x^4+5)-log(x^6+4) thanks Click to expand... What you wrote is equivalent to: \(\displaystyle Log[\frac{10x}{x}\cdot(x^4+5)\cdot(x^6+4)]\) or did you mean to write: \(\displaystyle Log[\frac{10x}{x\cdot(x^4+5)\cdot(x^6+4)}]\) Or something else.....
NadroJV13 said: Could someone help me expand this logarithm using the laws of lagarithms... log ( 10x/x(x^4+5)(x^6+4) ) My best guess was... x-logx-log(x^4+5)-log(x^6+4) thanks Click to expand... What you wrote is equivalent to: \(\displaystyle Log[\frac{10x}{x}\cdot(x^4+5)\cdot(x^6+4)]\) or did you mean to write: \(\displaystyle Log[\frac{10x}{x\cdot(x^4+5)\cdot(x^6+4)}]\) Or something else.....
