Exponential and logarithmic function questions.

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py1 - py2 = (e2x+3)/ex

p(ex+e-x)/2 - q(ex-e-x)/2 = (e2x+3)/ex

Multiplying both sides by 2ex yields
p(e2x + 1) - q((e2x - 1) = 2(e2x+3)

Now it is easy to see that p-q=2 and p+q = 6
 
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