so its
sqrt(3)^(2x+4)=9^(x-2)
Next step is
sqrt(3)^(2x+4)=(sqrt(3)^4)^(x-2)
sqrt(3)^(2x+4)=sqrt(3)^(4x-8)
Now that the bases are the same just equate the exponents.
2x+4=4x-8
You had better print out "Order of Operations" so you can check what you type. PEMDAS forever!!!
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