J Jen123 New member Joined Oct 21, 2006 Messages 31 Sep 12, 2007 #1 Problem: Write -1-i in exponential form. In my book it says theta= arctan b/a when a>0. but in the above equation a is -1 so how would I solve this.
Problem: Write -1-i in exponential form. In my book it says theta= arctan b/a when a>0. but in the above equation a is -1 so how would I solve this.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Sep 12, 2007 #2 \(\displaystyle \L \arg \left( { - 1 - i} \right) = \arctan \left( {\frac{{ - 1}}{1}} \right) - \pi\)
\(\displaystyle \L \arg \left( { - 1 - i} \right) = \arctan \left( {\frac{{ - 1}}{1}} \right) - \pi\)
