AustrianSaurkraut
New member
- Joined
- May 6, 2021
- Messages
- 14
For the curve f(x) = lnx/x2 with x>0. Find the coordinates of any critical points in exact answers only with no decimals.
For this question, I've been stuck on what to do after getting the derivative and how to solve for the critical points.
f'(x) = 2x(lnx)-1/x(x2)/(x2)2
f'(x) = 2x*lnx-x/x4
f'(x) = 2x*lnx-1/x3
Now from here is where I am clueless as to how to solve the equation, as I know you must set f'(x)=0 but I do not know how to solve with a lnx included. Any help will be greatly appreciated.
For this question, I've been stuck on what to do after getting the derivative and how to solve for the critical points.
f'(x) = 2x(lnx)-1/x(x2)/(x2)2
f'(x) = 2x*lnx-x/x4
f'(x) = 2x*lnx-1/x3
Now from here is where I am clueless as to how to solve the equation, as I know you must set f'(x)=0 but I do not know how to solve with a lnx included. Any help will be greatly appreciated.