Exponents exercise with steps pleas

[mikrochild]

Hello, I'm having a hard time solving this problem

I'm here

(x/y)^(a-1)=Px/Py

and I'm supposed to reach:

x/y=(Px/Py)^(1/a-1)

I know it may be kind of dumb not to know how to solve it but please help me

 

[Deleted member 4993]

Hello, I'm having a hard time solving this problem

I'm here

(x/y)^(a-1)=Px/Py

and I'm supposed to reach:

x/y=(Px/Py)^(1/a-1)

I know it may be kind of dumb not to know how to solve it but please help me

Do you see that you can use following property of exponents:

U ^ n = V →

U = V ^ (1/n)

In your problem: U = x/y &

V = P_x/P_y &

n = a-1

 

[BigBeachBanana]

[math]\text{In general, if } a^k=b\text{, then }a=b^{\frac{1}{k}}\\ \text{If } \left(\frac{x}{y}\right)^{a-1}=\frac{P_x}{P_y}, \text{then} \left(\frac{x}{y}\right)=\left(\frac{P_x}{P_y}\right)^{\frac{1}{a-1}}\\[/math]

 

[topsquark]

Hello, I'm having a hard time solving this problem

I'm here

(x/y)^(a-1)=Px/Py

and I'm supposed to reach:

x/y=(Px/Py)^(1/a-1)

I know it may be kind of dumb not to know how to solve it but please help me

Ahhh.... You meant (Px/Py)^(1/(a - 1)).

You need the parenthesis!

-Dan