f(x)=9(x+3)(x+2)^3 find the zeros

Find the zeros of this equation:

f(x)=9(x+3)(x+2)^3
Hint: The problem is f(x)=9times(x+3)times(x+2)^3. Now if you plug in a value for x then 9, x+3 and (x+2)^3 becomes a real number. Now when you multiply these numbers together you get 0. Can you think of three numbers that multiply out to 0? Another three numbers? Another three? Get the pattern?
Please come back and show us your work.
 
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