factor 12 x^4 + 25 x^2 + 12

a*(stuff)^2 + b*stuff + c

This should look familiar. If you have the quadratic formula, this sort of problem never should stop you.
 
galactus said:
I hate to ask, but are you really that lost?. 2 more steps and it's finished.

Maybe you should see your instructor.

Factor out 12x^2:

\(\displaystyle \L\\12x^{2}(x^{2}+12)+(x^{2}+12)\)

Surely you can finish now?. One more step.
yes i am pretty lost but yes i can work it from there thank you
 
galactus said:
Rewrite as: \(\displaystyle \L\\12x^{4}+24x^{2}+x^{2}+12\)

Now, group and factor. See?.
jenzbears said:
12x^4 +25x^2 + 12
but where do i start
Um... How about starting with what the tutor gave you, rather than ignoring it and returning to the original exercise...? :?:

Has your class not covered how to factor quadratics...?

Thank you. :D

Eliz.
 
galactus said:
Hello:

Rewrite as: \(\displaystyle \L\\12x^{4}+24x^{2}+x^{2}+12\)

Now, group and factor. See?.
There just seems that something is amiss here!

\(\displaystyle \L \begin{array}{rcl}
12x^4 + 25x^2 + 12 & = & 12x^4 + 24x^2 + x^2 + 12 \\
& = & 12x^2 \left( {x^2 + 2} \right) + \left( {x^2 + 12} \right) \\
\end{array}\)
 
pka said:
There just seems that something is amiss here!
Whoops! A typo, of course! :oops:

The better "in pairs" set-up would have been "12x<sup>4</sup> + 16x<sup>2</sup> + 9x<sup>2</sup> + 12.

Thank you for catching that! :D

Eliz.
 
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