H hgaon001 New member Joined May 17, 2009 Messages 39 Jun 9, 2009 #1 Its just a simple question... I know that (k+1)! is k!(k+1) But what about (2k+1)!?? how do u break that apart?
Its just a simple question... I know that (k+1)! is k!(k+1) But what about (2k+1)!?? how do u break that apart?
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jun 9, 2009 #2 \(\displaystyle (2k+1)! = (2k+1)[(2k)!]\)
