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factoring polynomials
- Thread starter zhaneil05
- Start date
\(\displaystyle 4(x-2)^{2}-8x(x-2)^{3}\)
Factor out the smallest power of (x-2) and a 4:
\(\displaystyle 4(x-2)^{2}(1-2x(x-2))\)
\(\displaystyle 4(x-2)^{2}(-2x^{2}+4x+1)\)
Factor out a -1 if you wish:
\(\displaystyle -4(x-2)^{2}(2x^{2}-4x-1)\)
Factor out the smallest power of (x-2) and a 4:
\(\displaystyle 4(x-2)^{2}(1-2x(x-2))\)
\(\displaystyle 4(x-2)^{2}(-2x^{2}+4x+1)\)
Factor out a -1 if you wish:
\(\displaystyle -4(x-2)^{2}(2x^{2}-4x-1)\)
Let a = x-2; then we have:zhaneil05 said:Factor completely
4(x-2)^2-8x(x-2)^3
4a^2 - 8xa^3
= 4a^2(1 - 2xa)
I find that a good way to "get going"....