Factoring problem

[Quasimoto]

Dear forum users,

I have been struggling with the following;



my book says I need to factor out as much as possible.

Now my book also says the solution to this is

Could someone explain to me how to get to this or if my book is wrong or where I can find some information about factoring.

I hope this is enough for you guys to help me out.

Thanks in advance.

 

[Deleted member 4993]

Dear forum users,

I have been struggling with the following;

View attachment 12760

my book says I need to factor out as much as possible.

Now my book also says the solution to this is View attachment 12761

Could someone explain to me how to get to this or if my book is wrong or where I can find some information about factoring.

I hope this is enough for you guys to help me out.

Thanks in advance.

I cannot read your first attachment. Please post a more legible copy.

In addition please follow our post-submission guideline enunciated at:

Posting Guidelines (Summary)

Welcome to our tutoring boards! :) This page summarizes some main points from our posting guidelines. As our name implies, we provide math help (primarily to students with homework). We do not generally post immediate answers or step-by-step solutions. We don't do your homework. We prefer to...

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[pka]

\(\displaystyle (a-1)^2(a+2)-(a-1)(a+2)^2\\(a-1)(a+2)\left[(a-1)-(a+2)\right]\)

 

[Quasimoto]

I cannot read your first attachment. Please post a more legible copy.

In addition please follow our post-submission guideline enunciated at:

Posting Guidelines (Summary)

Welcome to our tutoring boards! :) This page summarizes some main points from our posting guidelines. As our name implies, we provide math help (primarily to students with homework). We do not generally post immediate answers or step-by-step solutions. We don't do your homework. We prefer to...

www.freemathhelp.com

(a-1)^2(a+2) - (a-1)(a+2)^2

This is what the first attachment says, and thank you for the link.

 

[Deleted member 4993]

(a-1)^2(a+2) - (a-1)(a+2)^2

This is what the first attachment says, and thank you for the link.

Please continue working with hints provided in response #3 above.