factoring trinomials with decimals

debeez

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Jan 6, 2011
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Hi, I'am having trouble doing decimals. I know how to do it with normal numbers.
This problem has no common factors (v^2-0.1v-0.56) I know you have to find something that goes into
the sum and product but the decimal is throwing me off.


help! Thanks Debi
 
Would it be easier to work with this?

1100(100v2    10v  +  56)\displaystyle \frac{1}{100}\cdot\left(100\cdot v^{2}\;-\;10\cdot v \;+\;56\right)

Or maybe this?

150(50v2    5v  +  28)\displaystyle \frac{1}{50}\cdot\left(50\cdot v^{2}\;-\;5\cdot v \;+\;28\right)

Don't ever struggle through what you have been given. Find a way to make your life easier. In this case, why do you think it can be factored? That might be the simplest consideration.

Note: The fact that it has been given with two decimal places MAY indicate limited precision in the coefficients. A transformation to integers may not be appropriate.
 


Can you think of two numbers whose product is -56 and whose sum is -1 ?

Divide each of those numbers by 10, and use them in your factorization.

EG:

Factor v^2 + 0.9v + 0.20

We consider two numbers whose product is 20 and whose sum is 9. These numbers are 4 and 5.

Divide each by 10, and write the factorization.

(v + 0.4)(v + 0.5)


 
tkhunny said:
1100(100v2    10v  +  56)\displaystyle \frac{1}{100}\cdot\left(100\cdot v^{2}\;-\;10\cdot v \;+\;56\right)
150(50v2    5v  +  28)\displaystyle \frac{1}{50}\cdot\left(50\cdot v^{2}\;-\;5\cdot v \;+\;28\right)
Should be -56 and -28: go join Subhotosh in the corner ...
 
Gaaa...!! Transcription Failure! Sorry about that.
 
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