A Amster New member Joined Jan 6, 2010 Messages 1 Jan 6, 2010 #1 I don't understand how (x-17)/(x+2) + 13/6 becomes 19 (x-4)/6(x+2) when factoring. Can someone please explain?
I don't understand how (x-17)/(x+2) + 13/6 becomes 19 (x-4)/6(x+2) when factoring. Can someone please explain?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Jan 6, 2010 #2 It's just algebra. \(\displaystyle \frac{x-17}{x+2}+\frac{13}{6}\) This is finding a common denominator. Same as adding fractions. \(\displaystyle \frac{6}{6}\cdot \frac{(x-17)}{(x+2)}+\frac{13}{6}\cdot\frac{(x+2)}{(x+2)}\) Now, we have a common denominator: \(\displaystyle \frac{6(x-17)+13(x+2)}{6(x+2)}\) \(\displaystyle \frac{19x-76}{6(x+2)}\) Factor 19 out of the top: \(\displaystyle \frac{19(x-4)}{6(x+2)}\)
It's just algebra. \(\displaystyle \frac{x-17}{x+2}+\frac{13}{6}\) This is finding a common denominator. Same as adding fractions. \(\displaystyle \frac{6}{6}\cdot \frac{(x-17)}{(x+2)}+\frac{13}{6}\cdot\frac{(x+2)}{(x+2)}\) Now, we have a common denominator: \(\displaystyle \frac{6(x-17)+13(x+2)}{6(x+2)}\) \(\displaystyle \frac{19x-76}{6(x+2)}\) Factor 19 out of the top: \(\displaystyle \frac{19(x-4)}{6(x+2)}\)
