Hello,
I must find this limit with a Riemann sum. I see nothing, then is it possible please to have some help for starting please ?
lim x---> +inf x2 (1/(x+1)3 + 1/(x+2)3 + ....+ 1/(2x)3 )
My reasoning :
When x is big, x2 (1/(x+1)3) = ~ x2(1/x3) = 1/x
Then the sumn, we have x times ~[ (1/x + 1/8x)/2] when x is big.
Thanks
I must find this limit with a Riemann sum. I see nothing, then is it possible please to have some help for starting please ?
lim x---> +inf x2 (1/(x+1)3 + 1/(x+2)3 + ....+ 1/(2x)3 )
My reasoning :
When x is big, x2 (1/(x+1)3) = ~ x2(1/x3) = 1/x
Then the sumn, we have x times ~[ (1/x + 1/8x)/2] when x is big.
Thanks