supremacy32
New member
- Joined
- Aug 29, 2015
- Messages
- 9
Thanks for taking a look. I have a basic understanding of the material and was hoping to have someone doublecheck my work, and let me know if/where I went wrong.
Problem is as follows:
For the polynomial function f(x)= 3x4 - x3 + 3x2 + 29x -10
a) Find all possible rational zeros:
b) List the zeros of the function:
Solution:
a) Possible zeroes include -1, 1, -2, 2, -5, 5, -10, 10, -1/3, 1/3, -2/3, 2/3, -5/3, 5/3, -10/3, 10/3
b) Zeroes of the Function:
Using synthetic division and guessing and checking determine that 1/3 is a zero, making the equation f(x)=(x-(1/3))(3x3+3x+30)
Using synthetic division determine that -2 is now a zero, making the equation f(x)= (x-(1/3))(x+2)(3x2-5x+15)
Use quadratic equation to determine that remaining zeros are (5/6) ± (√155/6)i
Thus the zeros are 1/3, -2, and (5/6) ± (√155/6)i
On step b, I feel good until the zero that is a complex number. If someone would double check that part especially I would be grateful.
Problem is as follows:
For the polynomial function f(x)= 3x4 - x3 + 3x2 + 29x -10
a) Find all possible rational zeros:
b) List the zeros of the function:
Solution:
a) Possible zeroes include -1, 1, -2, 2, -5, 5, -10, 10, -1/3, 1/3, -2/3, 2/3, -5/3, 5/3, -10/3, 10/3
b) Zeroes of the Function:
Using synthetic division and guessing and checking determine that 1/3 is a zero, making the equation f(x)=(x-(1/3))(3x3+3x+30)
Using synthetic division determine that -2 is now a zero, making the equation f(x)= (x-(1/3))(x+2)(3x2-5x+15)
Use quadratic equation to determine that remaining zeros are (5/6) ± (√155/6)i
Thus the zeros are 1/3, -2, and (5/6) ± (√155/6)i
On step b, I feel good until the zero that is a complex number. If someone would double check that part especially I would be grateful.