C calculus1me New member Joined Feb 18, 2016 Messages 1 Feb 18, 2016 #1 Let . . . . .\(\displaystyle f(x)\, =\, \dfrac{x^2\, -\, 4}{x^2\, -\, 6x\, +\, 8}\) Use interval notation to indicate where f (x) is continuous. I can't figure out this problem. Please help me!! Attachments Screen Shot 2016-02-15 at 11.47.39 PM.png 28.2 KB · Views: 2 Last edited by a moderator: Feb 18, 2016
Let . . . . .\(\displaystyle f(x)\, =\, \dfrac{x^2\, -\, 4}{x^2\, -\, 6x\, +\, 8}\) Use interval notation to indicate where f (x) is continuous. I can't figure out this problem. Please help me!!
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Feb 18, 2016 #2 calculus1me said: Let . . . . .\(\displaystyle f(x)\, =\, \dfrac{x^2\, -\, 4}{x^2\, -\, 6x\, +\, 8}\) Use interval notation to indicate where f (x) is continuous. I can't figure out this problem. Click to expand... Use what you learned back in algebra. Where might a rational function not be continous? Where might it be broken up into two or more pieces? (here) If you get stuck (after reviewing at the link), please reply showing your efforts so far, starting with what you set equal to zero. Thank you!
calculus1me said: Let . . . . .\(\displaystyle f(x)\, =\, \dfrac{x^2\, -\, 4}{x^2\, -\, 6x\, +\, 8}\) Use interval notation to indicate where f (x) is continuous. I can't figure out this problem. Click to expand... Use what you learned back in algebra. Where might a rational function not be continous? Where might it be broken up into two or more pieces? (here) If you get stuck (after reviewing at the link), please reply showing your efforts so far, starting with what you set equal to zero. Thank you!