find limit, x -> 0, of [ sin(cos(2 pi)) ] / [ x sin(x) ], w/o l'Hospital's Rule

[memo]

Please help me solve this

\(\displaystyle \displaystyle \lim_{x\, \rightarrow\, 0}\, \)\(\displaystyle \dfrac{\sin\left(\cos(2 \pi)\right)}{x\, \sin(x)}\)

without using L' Hospital's rule

 

[Deleted member 4993]

Please help me solve this

lim sin(cos 2pi)/ (x sin x)
x->0

without using L' Hospital's rule

What are your thoughts?

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[Jedi Equester]

You should be able to simplify the nominator. Considering the denominator the limit is quite obvious?

 

[Prove It]

Please help me solve this

lim sin(cos 2pi)/ (x sin x)
x->0

without using L' Hospital's rule

The top is a constant. I don't see how you would be able to apply L'Hospital's Rule anyway...

Are you sure you copied the question correctly?