M Magadum Mukta New member Joined Jun 26, 2018 Messages 1 Jun 26, 2018 #1 Can anyone help me to find out A, B, C in this equation Z(i) = A (1- exp(-i/B)) + C when Z(1)=0 and Z(N)= LT
Can anyone help me to find out A, B, C in this equation Z(i) = A (1- exp(-i/B)) + C when Z(1)=0 and Z(N)= LT
D Deleted member 4993 Guest Jun 26, 2018 #2 Magadum Mukta said: Can anyone help me to find out A, B, C in this equation Z(i) = A (1- exp(-i/B)) + C when Z(1)=0 and Z(N)= LT Click to expand... In the equation above - Is i = \(\displaystyle \sqrt{-1} \ \)?
Magadum Mukta said: Can anyone help me to find out A, B, C in this equation Z(i) = A (1- exp(-i/B)) + C when Z(1)=0 and Z(N)= LT Click to expand... In the equation above - Is i = \(\displaystyle \sqrt{-1} \ \)?
Steven G Elite Member Joined Dec 30, 2014 Messages 14,603 Jun 26, 2018 #3 Magadum Mukta said: Can anyone help me to find out A, B, C in this equation Z(i) = A (1- exp(-i/B)) + C when Z(1)=0 and Z(N)= LT Click to expand... Z(0) = A (1 - 1) + C = 0. You can get some information from there. Can you please explain what N and LT represent?
Magadum Mukta said: Can anyone help me to find out A, B, C in this equation Z(i) = A (1- exp(-i/B)) + C when Z(1)=0 and Z(N)= LT Click to expand... Z(0) = A (1 - 1) + C = 0. You can get some information from there. Can you please explain what N and LT represent?