H hrr379 New member Joined Jun 9, 2012 Messages 17 Jun 14, 2012 #2 I think... Attachments photo (1).jpg 78.2 KB · Views: 2
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Jun 14, 2012 #3 Try expressing it in terms of powers of cos(2x).
S srmichael Full Member Joined Oct 25, 2011 Messages 848 Jun 15, 2012 #4 hrr379 said: I think... Click to expand... Or instead of doing u then v, just let u = sin2x and go from there.
hrr379 said: I think... Click to expand... Or instead of doing u then v, just let u = sin2x and go from there.