john458776
New member
- Joined
- May 15, 2021
- Messages
- 48
Please show us what you have tried and exactly where you are stuck.View attachment 27211
I really dont know how I'm going to solve this problem I tried and I'm not sure if I'm correct. please help me I'm practicing for my upcoming test.
The trouble is that 0⋅−∞ is indeterminate, so that the limit of the product depends on exactly how each factor approaches its own limit. It looks like sin(x)⋅ln(x), but that's quite different from "is". If k deviates from ln(x) in a significant way, the result may be entirely different.View attachment 27211
I really dont know how I'm going to solve this problem I tried and I'm not sure if I'm correct. please help me I'm practicing for my upcoming test.
Please show your work using "what skeeter has suggested ".The limit will be zero if I use what skeeter has suggested.
You can't - it can't be answered.I really dont know how I'm going to solve this problem
(For the final example [MATH]k(x)=-e^{\frac{1}{x}}[/MATH] equivalently).
Missed that. Thanks.may want to add a positive constant to k(x) to get an x-intercept ... on all the examples
That's beautiful, but I think that the main idea of this question is that to let the student to pick any two functions that are similar to the graph and proves his/her answer. It does not matter what is the answer.(Repost of #9, incorporating skeeter's suggested amendment).
You can't - it can't be answered.
E.g.
[MATH]g(x)=\sin \left(\frac{x}{10}\right)[/MATH], [MATH]\hspace2ex k(x)=-\frac{1}{\sqrt{x}}+\frac{1}{2}[/MATH], [MATH]\hspace2ex \lim \limits_{x \to 0^{+}} g(x)k(x)=0[/MATH]View attachment 27233
[MATH]g(x)=\sin \left(\frac{x}{10}\right)[/MATH], [MATH]\hspace2ex k(x)=-\frac{1}{x}+\frac{1}{2}[/MATH], [MATH]\hspace2ex \lim \limits_{x \to 0^{+}} g(x)k(x)=-\frac{1}{10}[/MATH]View attachment 27234
[MATH]g(x)=\sin \left(\frac{x}{10}\right)[/MATH], [MATH]\hspace2ex k(x)=-e^{\frac{1}{x}}+\frac{3}{2}[/MATH], [MATH]\hspace2ex \lim \limits_{x \to 0^{+}} g(x)k(x)=-\infty[/MATH]View attachment 27235
That's possible, but it's not an appropriate thing to do on a test, without explicitly stating it.That's beautiful, but I think that the main idea of this question is that to let the student to pick any two functions that are similar to the graph and proves his/her answer. It does not matter what is the answer.
You are correct Dr.Peterson.That's possible, but it's not an appropriate thing to do on a test, without explicitly stating it.
I dislike problems that penalize diligent students who want to be sure they are correct, and realize there is not one right answer (perhaps after a long struggle). If a problem says "find ___", it implies there is a specific ___ to be found.
Students who are used to guessing answers on tests, and assuming things they don't know, would have less trouble. That is not what should be taught in a math class.