Find the slope-intercept form of the equation of the line...

[RicanGurl]

Find the slope-intercept form of the equation of the line through the point (0,9), perpendicular to the graph of y=2x+ 1/1/3 .

 

[jwpaine]

Re: Find the slope-intercept form of the equation of the lin

Find the slope-intercept form of the equation of the line through the point (0,9), perpendicular to the graph of y=2x+ 1/1/3 .

slope = m = 2

A slope perpendicular to 2 will be the multiplicative inverse with sign change, thus -(1/2) is perpendicular to 2 because -(1/2)2 = -1

Use the point-slope form for the equation of a line: y - y1 = m(x - x1). Plug and chug your values (x1, y1) from your ordired pair into the point-slope equation with your new perpendicular slope and then put it in the form of y = mx+b

 

[RicanGurl]

I tried to do the problem and I got y = -1/2x + 9

am I right?

 

[jwpaine]

I tried to do the problem and I got y = -1/2x + 9

am I right?

y - 9 = -(1/2)(x - 0)

y = -(1/2)x + 9

Correct!

 

[Mrspi]

I tried to do the problem and I got y = -1/2x + 9

am I right?

Yes.