Elizabeth083
New member
- Joined
- Mar 3, 2021
- Messages
- 2
Hello,
The question is: Find the least degree polynomial function with zeroes: -1-3i, and 4 with a multiplicity of 4.
And, f(0)=215.
I understand the factors to thus be: (x-4)^4, and (x+(-1-3i)) and (x+(-1+3i)).
I simplify to get this: f(x)=(x-4)^4(x-1-3i)(x-1+3i)
But another aspect of the question is the Y intercept, because it says the function must contain f(0)=215. I'll call the missing value for this "a".
So to find A, I do this:
215=a (0-4)^3) (0-1-3i) (0-1+3i)
And I get A= 0.083984375
so final function: f(x)=0.083984375((x-4)^4 (x-1-3i) (x-1+3i)
Have I made mistakes?
The question is: Find the least degree polynomial function with zeroes: -1-3i, and 4 with a multiplicity of 4.
And, f(0)=215.
I understand the factors to thus be: (x-4)^4, and (x+(-1-3i)) and (x+(-1+3i)).
I simplify to get this: f(x)=(x-4)^4(x-1-3i)(x-1+3i)
But another aspect of the question is the Y intercept, because it says the function must contain f(0)=215. I'll call the missing value for this "a".
So to find A, I do this:
215=a (0-4)^3) (0-1-3i) (0-1+3i)
And I get A= 0.083984375
so final function: f(x)=0.083984375((x-4)^4 (x-1-3i) (x-1+3i)
Have I made mistakes?