Finding an equation for an ellipse

[norton]

I have to find an equation for the ellipse I have in a figure. The figue is not on the origin but left of the y axis and opens vertically.
The top most points are (-3,7)
The bottom most points are (-3,-1)
The right most points are (-1,3)
The left most points are (-5,3)


I have these equations for possible answers:

a.) (x-3)^2/2 + (y+3)^2/4 =1
b.) (x-3)^2/4 + (y+3)^2/16 =1
c.) (x+3)^2/2 + (y-3)^2/4 = 1
d.) (x+3)^2/4 + (y-3)^2/16 = 1

I believe my center will be points (-3,3)
I ruled out answers a & b because these would not give me a center (-3,3)
Using answer d:
I counted 2 units from center left and right. This will give vertices on the minor axis as (-5,3), (-1,3)
I counted 4 units from center up and down. This will give vertices on the major axis as (-3,7), (-3,-1).
I am not sure if this is the correct way of doing this.
[/img]

Answer D has the center points that would correspond to (-3,3)

 

[stapel]

Hint: Given the listed points, what is the center?

Eliz.

 

[norton]

From examples of other problems I have seen are not the center points the numbers associated with x & y and then use the opposite? So are not my center points (-3,3) or am I confused?

 

[stapel]

Which of the given answer option(s) has this as the center point?

Eliz.

 

[norton]

I have to find an equation for the ellipse I have in a figure. The figue is not on the origin but left of the y axis and opens vertically.
The top most points are (-3,7)
The bottom most points are (-3,-1)
The right most points are (-1,3)
The left most points are (-5,3)


I have these equations for possible answers:

a.) (x-3)^2/2 + (y+3)^2/4 =1
b.) (x-3)^2/4 + (y+3)^2/16 =1
c.) (x+3)^2/2 + (y-3)^2/4 = 1
d.) (x+3)^2/4 + (y-3)^2/16 = 1

I believe my center will be points (-3,3)
I ruled out answers a & b because these would not give me a center (-3,3)
Using answer d:
I counted 2 units from center left and right. This will give vertices on the minor axis as (-5,3), (-1,3)
I counted 4 units from center up and down. This will give vertices on the major axis as (-3,7), (-3,-1).
I am not sure if this is the correct way of doing this.
[/img]

Answer D has the center points that would correspond to (-3,3)

CORRECTION: I missed type the wrong sign for y in answer d. the correct sign should be a minus sign. I apologize for the mistake. I thought I had checked them for correctness.