Hello,
I'm new here and I'm not really sure if I'm doing this correctly, so I apologize if I make any horrible posting errors.
I have to find the derivative of y=sqrt((3x2+2)3)
I'm unsure about the order that I need to apply the square root/exponent.
Here is what I have:
y'=((3x2+2)3)1/2
=(3x2+2)1.5
=1.5(3x2+2)0.5(6x)
Is this correct?
Any help would be appreciated, thank you!
I'm new here and I'm not really sure if I'm doing this correctly, so I apologize if I make any horrible posting errors.
I have to find the derivative of y=sqrt((3x2+2)3)
I'm unsure about the order that I need to apply the square root/exponent.
Here is what I have:
y'=((3x2+2)3)1/2
=(3x2+2)1.5
=1.5(3x2+2)0.5(6x)
Is this correct?
Any help would be appreciated, thank you!