RyanGall93
New member
- Joined
- May 2, 2019
- Messages
- 8
Nah I can’t. I don’t have a great eye for calculus I’m afraid.If I were to proceed using my suggestion, I would get:
[MATH]-\sin(y)\d{y}{x}=\frac{1}{2\sqrt{x}}[/MATH]
[MATH]\d{y}{x}=-\frac{1}{2\sqrt{x}\sin(y)}=-\frac{1}{2\sqrt{x-x^2}}[/MATH]
Do you see that you'd get the same from pka's suggestion?
Your method was correct, you just made some slips in the details. can you spot them?
x^-1/2What does du/dx = ??
That is not true. Consider what the derivative of x3 is wrt x, is it x2?x^-1/2