W warsatan New member Joined Sep 12, 2005 Messages 36 Sep 12, 2005 #1 just want to say hello, this is my first post here and i have this problem due in a bit. thanks if you can help out. f(x) = (x+2)/x find the inverse, thanks again.
just want to say hello, this is my first post here and i have this problem due in a bit. thanks if you can help out. f(x) = (x+2)/x find the inverse, thanks again.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Sep 12, 2005 #2 The usual process for finding an inverse is as follows: . . . . .1) Rename "f(x)" as "y". . . . . .2) Solve for "x=". . . . . .3) Switch "x" and "y". . . . . .4) Rename the new "y" as "f<sup>-1</sup>(x)". So you'd start like this: . . . . .f(x) = (x + 2)/x . . . . .y = (x + 2)/x . . . . .xy = x + 2 . . . . .xy - x = 2 . . . . .x(y - 1) = 2 ...and so forth. Eliz.
The usual process for finding an inverse is as follows: . . . . .1) Rename "f(x)" as "y". . . . . .2) Solve for "x=". . . . . .3) Switch "x" and "y". . . . . .4) Rename the new "y" as "f<sup>-1</sup>(x)". So you'd start like this: . . . . .f(x) = (x + 2)/x . . . . .y = (x + 2)/x . . . . .xy = x + 2 . . . . .xy - x = 2 . . . . .x(y - 1) = 2 ...and so forth. Eliz.
W warsatan New member Joined Sep 12, 2005 Messages 36 Sep 12, 2005 #3 wow, that was quick, i got it now, thanks a lot for your help, this forum is awesome