In the following figure, line segment AB is parallel to line segment CD, m of angle BAE = 41 degrees, and m of angle BED = 76 degrees, find the measures of angles CDE, DCE, and ABD, if possible.
The angle of BED is 76, I know that from A to D is 180 degrees. So I subtracted 76 from 180 and got 104 for angle angle AEB. I also know that a complete triangle measures 180 degrees so I added 104 + 41 (angle BAE) =145. Subtracting that sum from 180 gives me the missing angle of ABE which is 35 degrees.
Another step I did was seen that B to C equals 180 degrees and angle BED was already provided (76 degrees). So I subtracted. 180 - 76 = 104. That gave me angle CED as 104 degrees.
This is where I am stuck. I cannot seem to find a way to find the other missing angles needed. Can anyone point me in the right direction? Thanks so much!
The angle of BED is 76, I know that from A to D is 180 degrees. So I subtracted 76 from 180 and got 104 for angle angle AEB. I also know that a complete triangle measures 180 degrees so I added 104 + 41 (angle BAE) =145. Subtracting that sum from 180 gives me the missing angle of ABE which is 35 degrees.
Another step I did was seen that B to C equals 180 degrees and angle BED was already provided (76 degrees). So I subtracted. 180 - 76 = 104. That gave me angle CED as 104 degrees.
This is where I am stuck. I cannot seem to find a way to find the other missing angles needed. Can anyone point me in the right direction? Thanks so much!