A andie New member Joined Jan 6, 2009 Messages 5 Feb 3, 2009 #1 I have the equation y=1/2cos(2x/3) The period is 3? and the amplitude is 1/2 I know how to get the amplitude, but I need help on how to get the period
I have the equation y=1/2cos(2x/3) The period is 3? and the amplitude is 1/2 I know how to get the amplitude, but I need help on how to get the period
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Feb 3, 2009 #2 Re: Finding Period and Amplitude Show that \(\displaystyle y(x+3\pi)=y(x)\).
W wjm11 Senior Member Joined Nov 13, 2004 Messages 1,417 Feb 4, 2009 #3 Re: Finding Period and Amplitude I have the equation y=1/2cos(2x/3) The period is 3? and the amplitude is 1/2 I know how to get the amplitude, but I need help on how to get the period Click to expand... Use the coefficient of x. In general, let’s call it variable B. The relationship between B and the period of the function, P, is simple: B = 2pi/P The “2pi” applies to both sine and cosine functions. This can also be rearranged to read P = 2pi/B In this case B = 2/3. Therefore, P = 2pi/(2/3) = 3pi If you are working in degrees rather than radians, use 360 in place of 2pi. Hope that helps.
Re: Finding Period and Amplitude I have the equation y=1/2cos(2x/3) The period is 3? and the amplitude is 1/2 I know how to get the amplitude, but I need help on how to get the period Click to expand... Use the coefficient of x. In general, let’s call it variable B. The relationship between B and the period of the function, P, is simple: B = 2pi/P The “2pi” applies to both sine and cosine functions. This can also be rearranged to read P = 2pi/B In this case B = 2/3. Therefore, P = 2pi/(2/3) = 3pi If you are working in degrees rather than radians, use 360 in place of 2pi. Hope that helps.
