B becky i New member Joined Jan 27, 2009 Messages 1 Jan 27, 2009 #1 A room is 10 ft 6 inches by 14 ft 3 inches how many square yards of carpet are needed to cover the floor? Becky
A room is 10 ft 6 inches by 14 ft 3 inches how many square yards of carpet are needed to cover the floor? Becky
W wjm11 Senior Member Joined Nov 13, 2004 Messages 1,417 Jan 27, 2009 #2 A room is 10 ft 6 inches by 14 ft 3 inches how many square yards of carpet are needed to cover the floor? Becky Click to expand... Hello, Becky, What have you tried so far? One approach might be to convert everything to inches first: 10 ft 6 inches = 120 + 6 = 126 inches 14 ft 3 inches = 168 + 3 = 171 inches next find the area in square inches: 171(126) = 21546 in^2 Now you’ll need to convert to square yards. Your turn.
A room is 10 ft 6 inches by 14 ft 3 inches how many square yards of carpet are needed to cover the floor? Becky Click to expand... Hello, Becky, What have you tried so far? One approach might be to convert everything to inches first: 10 ft 6 inches = 120 + 6 = 126 inches 14 ft 3 inches = 168 + 3 = 171 inches next find the area in square inches: 171(126) = 21546 in^2 Now you’ll need to convert to square yards. Your turn.
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Jan 27, 2009 #3 Hello, Becky! A room is 10 ftm 6 inches by 14 ft, 3 inches How many square yards of carpet are needed to cover the floor? Click to expand... \(\displaystyle \text{10 ft, 6 inches} \:=\:10\tfrac{1}{2}\text{ ft} \:=\:\tfrac{21}{2}\text{ ft}\) \(\displaystyle \text{14 ft, 3 inches} \:=\:14\tfrac{1}{4}\text{ ft} \:=\:\tfrac{57}{4}\text{ ft}\) \(\displaystyle \text{The area is: }\:\frac{21}{2} \times \frac{57}{4} \:=\:\frac{1197}{8}\text{ ft}^2\) \(\displaystyle \text{Since: }\:\text{1 yd}^2 \:=\:9\text{ ft}^2\!:\) . . \(\displaystyle \text{we have: }\:\frac{1197}{8} \div 9 \:=\:\frac{133}{8}\:=\:16\tfrac{5}{8}\text{ yd}^2\)
Hello, Becky! A room is 10 ftm 6 inches by 14 ft, 3 inches How many square yards of carpet are needed to cover the floor? Click to expand... \(\displaystyle \text{10 ft, 6 inches} \:=\:10\tfrac{1}{2}\text{ ft} \:=\:\tfrac{21}{2}\text{ ft}\) \(\displaystyle \text{14 ft, 3 inches} \:=\:14\tfrac{1}{4}\text{ ft} \:=\:\tfrac{57}{4}\text{ ft}\) \(\displaystyle \text{The area is: }\:\frac{21}{2} \times \frac{57}{4} \:=\:\frac{1197}{8}\text{ ft}^2\) \(\displaystyle \text{Since: }\:\text{1 yd}^2 \:=\:9\text{ ft}^2\!:\) . . \(\displaystyle \text{we have: }\:\frac{1197}{8} \div 9 \:=\:\frac{133}{8}\:=\:16\tfrac{5}{8}\text{ yd}^2\)