Finding tangential and normal acceleration

PequodLZ

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Mar 25, 2021
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I have a particle moving in a circle with radius 1 that is accelerating at 1m/s2 that started from rest
I need to find its tangential and normal acceleration when its velocity is 1m/s
Naturally it will achieve 1m/s velocity after 1s

I know that a2=atangential2+anormal2
I know that atangential= (dv/dt)
I know that anormal= v2/r

So this gives me a2=(dv/dt)2+(v2/r)2
We have a=1m/s2 and r=1 and t=1s
So it then becomes 1=((v-0)/1)2+(v2/1)2
This gives me v=0.786151377

Plugging it back in the tangential and normal velocity vectors I get
atangential= (dv/dt) = 0.786151377m/s2
anormal= v2/r = 0.6180339887m/s2

Am I right or was my logic flawed at some point?
 
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