Finding the angle of intersection between 2 curves: y=x^3-5 and y=5x^2-x

[bouhrassa]

Just want to check my math with you guys. I must find the angle between y=x^3-5 and y=5x^2-x

1. I found the point of intersection x=5

2. I derivate the 2 curves and check the slope at x=5
That gives me m1=75 and m2=49

3. I use the formula tan(@) = (m1-m2)/(1+m1*m2)
My result is angle = 0.41 degree

Thank you

 

[Deleted member 4993]

Just want to check my math with you guys. I must find the angle between y=x^3-5 and y=5x^2-x

1. I found the point of intersection x=5

2. I derivate the 2 curves and check the slope at x=5
That gives me m1=75 and m2=49

3. I use the formula tan(@) = (m1-m2)/(1+m1*m2)
My result is angle = 0.41 degree

Thank you

Looks good to me.