Finding the area of a cube

BMWrider

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Aug 23, 2007
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I'm stuck on where to begin on this problem. thanks for any help!

The volume of the box is represented by (x^2 + 5x + 6)(x + 5). Find the polynomial that represents the area of the bottom of the box. The height of the box is x + 2.
 
BMWrider said:
I'm stuck on where to begin on this problem. thanks for any help!

The volume of the box is represented by (x^2 + 5x + 6)(x + 5). Find the polynomial that represents the area of the bottom of the box. The height of the box is x + 2.

V = (x^2 + 5x + 6)(x + 5)

V = (x+3)(x+2)(x + 5)

Now continue....
 
In my opinion, this is a poorly stated problem. As the previous responder stated...
V = (x+3)(x+2)(x + 5)
The volume is the result of multiplying the area of the base times its height.
Of course, it depends on which of the faces of the box it is sitting. You have three different results depending on which face you want to call the base.

In V = (x^2 + 5x + 6)(x + 5), x^2+5x+6 could represent the base.
In V = (x^2 + 8x +15)(x+2), x^2 + 8x +15 can represent the base.
In V = (x^2+7x+10)(x+3), x^2+7x+10 can represent the base.
 
thanks for your help

I agree its poorly stated...but that the EXACT way it was written in the book!

both of your helps helped!!!! 8-)
 
The problem DOES state that the height of the box is (x + 2)

Once you've factored the trinomial as suggested by the previous responder, and have

Volume = (x + 3)(x + 2)(x + 5)

you may wish to recall that

Volume = (area of base)*(height)

We know that the height is (x + 2).....the problem says so. Rearrange to put the factor of (x + 2) at the "end." Thus, the remaining two factors (x + 3)(x + 5) must give the area of the base:

Volume = [(x + 3)(x + 5)] * (x + 2)

Now, multiply out (x + 3)(x + 5) to find the polynomial which represents the area of the base.
 
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